Another postulate is that during the seasons when the sun shines on the equator, I imagine that when it is directly over the equator it gives the surface side inhabitants 12 (out of 24) hours of daylight, so when it is at 45 degrees in the sky it would only provide 6 hours of daylight.
The final postulate is that there is a space elevator, and a city in geosynchronous orbit, based on the equator. A trip to or from the orbital city takes 4 days.
My question is, how long would the station pass through the shadow of the world on days when the sun peaks at 45 degrees over the equator?
Likewise, I figure the crawler that travels up and down the elevator would spend more and more time in darkness the closer it is to the surface ... is there some kind of formula I could use to calculate the length of time the crawler is in shadow for each day? If so what is it?
Thanks for your help in this matter.
the G-man Himself
Edited by G-man, 07 July 2019 - 07:52 AM.